Question

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Answer 1

Where's the question...?

Answer 2

Now - I appreciate that you are probably answering an online multichoice option - but strictly speaking NONE of those options are true.

Electrons carry a negative charge, and will always flow towards the positive side of the circuit.

However - a capacitor does not actually have a current 'through' it, so neither of the options 'starting from the negative end of the battery' is quite correct.

Answer 3

Since the resistors are all in series they have the SAME current flowing through them

Power = I^2 R

Answer 4

The resistors are all in series - so it is simple to find their combined resistance.

Foe the whole circuit use ohms law to find the current

Answer 5

Because this is a series circuit - the SAME current flows through ALL resistors

You have made the mistake of applying the same VOLTAGE across each, whereas you can see that the voltage is applied across the ends of the series - so each resistor has a different voltage.

Treat the circuit as a whole - work out the toatla resistance

Using that total resistance work out the current

The for EACH resistr Power = I^2 R

Answer 6

You do have the equation for total resistance - they are in series

Answer 7

yes, if you have series resistors, the effective (or total) resistance is \[R_{eff} = R_1 + R_2 + ... + R_n\]

If you have parallel resistors, the effective resistance is \[R_{eff} = \frac{1}{\frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}}\]

Answer 8

The third choice is the best choice. There will be an initial flow electrons until the Capacitor is charged up to value that of the applied voltage (battery).

Answer 9

@radar
But - in order for the capacitor to charge electrons must flow in the resistors as well, so neither option is correct

Answer 10

@MrNood Of course it is indeed a series circuit. I thought choice c included the resistors in the charge path. The choices have been deleted so I am not able to verify.

Answer 11

hu