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Mathematics 17 Online
OpenStudy (anonymous):

arccos(2cos^2(3pi/8)-1)

OpenStudy (anonymous):

First find out value of 2cos^2(3pi/8) = ----? can you try ?

OpenStudy (anonymous):

I have tried but I've been unsuccessful, I'm meant to evaluate without the use of a calculator

OpenStudy (anonymous):

use cos^2(x) = (1/2) (cos(2x) +1)

OpenStudy (anonymous):

Yes, I've already done so, but i'm stuck after that

OpenStudy (anonymous):

what did you get afterward?

OpenStudy (anonymous):

Nothing, I'm utterly confounded after this step

OpenStudy (anonymous):

did you have arccos(cos(3pi/4)) ?

OpenStudy (anonymous):

since 0<= 3pi/4 <= pi, 3pi/4 is your final answer

OpenStudy (anonymous):

how did you get arccos(cos(3pi/4))?

OpenStudy (anonymous):

using the formula above I gave you

OpenStudy (anonymous):

cos^2(3pi/8) = (1/2) (cos(2 * 3pi/8) + 1)

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