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arccos(2cos^2(3pi/8)-1)
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First find out value of 2cos^2(3pi/8) = ----? can you try ?
I have tried but I've been unsuccessful, I'm meant to evaluate without the use of a calculator
use cos^2(x) = (1/2) (cos(2x) +1)
Yes, I've already done so, but i'm stuck after that
what did you get afterward?
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Nothing, I'm utterly confounded after this step
did you have arccos(cos(3pi/4)) ?
since 0<= 3pi/4 <= pi, 3pi/4 is your final answer
how did you get arccos(cos(3pi/4))?
using the formula above I gave you
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cos^2(3pi/8) = (1/2) (cos(2 * 3pi/8) + 1)
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