Trigonometry
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OpenStudy (anonymous):
verify equation identity
(1-cot^2)/(1+cot^2)+1=2 sin^2
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OpenStudy (anonymous):
I try solving it and it was not an identity but I am not sure I am right.
OpenStudy (anonymous):
|dw:1398203236677:dw|
OpenStudy (anonymous):
yeah i I did that but at the end of it I did not get the 2sin^2
OpenStudy (anonymous):
|dw:1398203617892:dw|
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
At the end use property sin^2 + cos^2 = 1
OpenStudy (anonymous):
at denominator
OpenStudy (anonymous):
yeah that would give me 1/sin^2
OpenStudy (anonymous):
Please check it
OpenStudy (anonymous):
wait would my denominator be (sin^2+cos^2)/ sin^2?
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OpenStudy (anonymous):
|dw:1398204432505:dw|
OpenStudy (anonymous):
|dw:1398204540377:dw|
OpenStudy (anonymous):
similarly at denominatior , so sin^2 get cancel from both numerator & denominator ..
OpenStudy (anonymous):
oh wow. so there would only be left -cos^2 right
OpenStudy (anonymous):
|dw:1398204881696:dw|
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OpenStudy (anonymous):
Okay
?
OpenStudy (anonymous):
yeah i understand that
OpenStudy (anonymous):
what would be the next step ?
OpenStudy (anonymous):
lcd
OpenStudy (anonymous):
Are you there ?
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OpenStudy (anonymous):
use the denominator equal one
OpenStudy (anonymous):
|dw:1398205488285:dw|
OpenStudy (anonymous):
So what do you get ?
OpenStudy (anonymous):
at the top part do you multiply the a times y?
OpenStudy (anonymous):
in our step x = (sin^2 - cos^ ) & y = sin^2 + cos^2 & a = 1
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OpenStudy (anonymous):
yes so it would be sin^2-cos^2+(sin^2-cos^2) all divided by sin^2+cos^2?
OpenStudy (anonymous):
okay I understood it never mine. Thank you so much for your help. I did get 2sin^2 at the end.
OpenStudy (anonymous):
You are welcome :)