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Trigonometry 9 Online
OpenStudy (anonymous):

verify equation identity (1-cot^2)/(1+cot^2)+1=2 sin^2

OpenStudy (anonymous):

I try solving it and it was not an identity but I am not sure I am right.

OpenStudy (anonymous):

|dw:1398203236677:dw|

OpenStudy (anonymous):

yeah i I did that but at the end of it I did not get the 2sin^2

OpenStudy (anonymous):

|dw:1398203617892:dw|

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

At the end use property sin^2 + cos^2 = 1

OpenStudy (anonymous):

at denominator

OpenStudy (anonymous):

yeah that would give me 1/sin^2

OpenStudy (anonymous):

Please check it

OpenStudy (anonymous):

wait would my denominator be (sin^2+cos^2)/ sin^2?

OpenStudy (anonymous):

|dw:1398204432505:dw|

OpenStudy (anonymous):

|dw:1398204540377:dw|

OpenStudy (anonymous):

similarly at denominatior , so sin^2 get cancel from both numerator & denominator ..

OpenStudy (anonymous):

oh wow. so there would only be left -cos^2 right

OpenStudy (anonymous):

|dw:1398204881696:dw|

OpenStudy (anonymous):

Okay ?

OpenStudy (anonymous):

yeah i understand that

OpenStudy (anonymous):

what would be the next step ?

OpenStudy (anonymous):

lcd

OpenStudy (anonymous):

Are you there ?

OpenStudy (anonymous):

use the denominator equal one

OpenStudy (anonymous):

|dw:1398205488285:dw|

OpenStudy (anonymous):

So what do you get ?

OpenStudy (anonymous):

at the top part do you multiply the a times y?

OpenStudy (anonymous):

in our step x = (sin^2 - cos^ ) & y = sin^2 + cos^2 & a = 1

OpenStudy (anonymous):

yes so it would be sin^2-cos^2+(sin^2-cos^2) all divided by sin^2+cos^2?

OpenStudy (anonymous):

okay I understood it never mine. Thank you so much for your help. I did get 2sin^2 at the end.

OpenStudy (anonymous):

You are welcome :)

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