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how do i do this?
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\[\sqrt{3x-2}-\sqrt{x+7}-1\]
@KingGeorge
Do you want to solve for the roots?
it just says on here to solve the given equation so i think so
do i square both sides?
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You could, but in this case, squaring immediately will be difficult and time consuming. The first thing you want to do, is move some stuff over the other side. Like so:\[\sqrt{3x-2}-\sqrt{x+7}-1=0\implies\sqrt{3x+2}=\sqrt{x+7}+1\]Now you should square it.
Remember that \(\sqrt{x}^2=x\) and not \(x^2\). Also, you will need to FOIL the right side. So it should be more like\[(\sqrt{3x+2})^2=(\sqrt{x+7}+1)^2\]\[3x+2=(x+7)+2\sqrt{x+7}+1\]\[2x-6=2\sqrt{x+7}\]\[x-3=\sqrt{x+7}\]Does this make sense?
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