Light with a wavelength of 5.0 · 10-7 m strikes a surface that requires 2.0 ev to eject an electron. Calculate the maximum KE, in electron volts, of the emitted photoelectron.

Question

anonymous · Answer

convert wavelength to energy, h c/ lambda
put in units of electron-volts
subtract 2 eV to determine max left for kinetic energy of ejected electron

anonymous · Answer

Could you explain that a little more?

anonymous · Answer

@douglaswinslowcooper

sidsiddhartha · Answer

max kinetic energy=hc/lamda-workfunction=2.484-2=0.484

anonymous · Answer

Thank you, that makes more sense.