Question

Light with a wavelength of 5.0 · 10-7 m strikes a surface that requires 2.0 ev to eject an electron. Calculate the maximum KE, in electron volts, of the emitted photoelectron.

Answer 1

convert wavelength to energy, h c/ lambda
put in units of electron-volts
subtract 2 eV to determine max left for kinetic energy of ejected electron

Answer 2

Could you explain that a little more?

Answer 3

@douglaswinslowcooper

Answer 4

max kinetic energy=hc/lamda-workfunction=2.484-2=0.484

Answer 5

Thank you, that makes more sense.