plz help

Suppose a cylindrical barrel falls off a ship and sinks to the bottom of the sea at a depth of 1.61 km. Assume that the seawater is incompressible, so that its density at the bottom of the sea is the same at the surface :1020 kg/m^3

If the pressure inside the barrel is 1.00 atm (it was sealed at sea level) and the total surface area of the barrel is 3.50 m^2 , find the NET INWARD FORCE acting on the surface of the barrel when it reaches the bottom of the ocean.

Question

plz help


Suppose a cylindrical barrel falls off a ship and sinks to the bottom of the sea at a depth of 1.61 km. Assume that the seawater is incompressible, so that its density at the bottom of the sea is the same at the surface :1020 kg/m^3

If the pressure inside the barrel is 1.00 atm (it was sealed at sea level) and the total surface area of the barrel is 3.50 m^2 , find the NET INWARD FORCE acting on the surface of the barrel when it reaches the bottom of the ocean.

praxer · Answer

total pressure acting = atmospheric pressure + pressure with depth
= 1.01*10^5 pa (atmospheric pressure) + h ro g ( pressure due to depth)
=1.01*10^5 + 1610m*1020*10
=165.2*10^5pa
=165.2atm

now pressure = force /area
force = pressure * area
         =165.2*10^5*3.50
          =578.2*10^5 Newton.

praxer · Answer

@missylulu  did you understand it.:)

anonymous · Answer

@praxer yeah thanks so much!!! :)))

praxer · Answer

$$\huge \frak \color{red}{WELCOME....\ddot\smile}$$