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Mathematics 8 Online
OpenStudy (anonymous):

please help

OpenStudy (anonymous):

OpenStudy (anonymous):

just do the same thing as the first one

OpenStudy (anonymous):

i know but i have problems adding and getting another mixed number

OpenStudy (sidsiddhartha):

5(2/5)

OpenStudy (anonymous):

thanks @sidsiddhartha

OpenStudy (anonymous):

giveing them the answer is not right they need to learn

OpenStudy (anonymous):

$$4 \frac{1}{5} + b = 9\frac{3}{5} $$ Bring 4 (1/5) over to the right side of the equation: $$b = 9\frac{3}{5} - 4 \frac{1}{5} $$ Subtract whole numbers (9-4) then subtract fractions (3/5 - 1/5) $$b = 5\frac{2}{5} $$

OpenStudy (mathmale):

Several observations: your LCD ("lowest common denominator) is 5. Re-write 4 1/5 and 9 3/5 as improper fractions: 4 1/5 becomes (4*5+1)/5, and 9 3/5 becomes ... ??? Next, multiply EVERY term in your latest equation by 5, to eliminate the fractions. Rearrange your equation so that 5b is on the left and the other terms are on the right. Divide this latest who equation thru by 5 and you'll have the value of b.

OpenStudy (sidsiddhartha):

sorry bout that

OpenStudy (mathmale):

\[4\frac{ 1 }{ 5}=\frac{ 21 }{ 5 }~and ~9\frac{ 2 }{ 5 }=\frac{ 47 }{ 5 }\]

OpenStudy (mathmale):

Re-write the original equation accordingly. Again, multiply the whole equation thru by 5. Isolate 5b on the left. Divide everything by 5 to obtain an equation for the value of b. Unfortunately, I have to get off the 'Net now. hope these suggestions at least get you started in the right direction!

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