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A complex trigonometry problem
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If the angles A, B and C of a triangle are in an arithmetic progression and if a, b and c denote the lengths of the sides opposite to A,B and C respectively then value of the expression (a/c)sin2C+(c/a)sin2A is
|dw:1398253611289:dw|
I got angle B as 60 degrees
\(A + (A+d) + (A+2d) = \pi\) \(\implies d = \dfrac{\pi}{3} - A\) that gives : \(B = \dfrac{\pi}{3} \\ A+C = \dfrac{2\pi}{3}\)
Yeah that's what B is 60 degrees
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