Question

Help?

Answer 1

@mathmale

Answer 2

can you explain how to do it

Answer 3

Hello!
There is a special form of the function describing the parabola that includes the vertex:

\[y=a(x-h)^2+k\]

Answer 4

Have you seen this before? If you were to take the given function, y=x^2 + 2x + 1 and rewrite it in that form, the coordinates of the vertex would be immediately apparent.

Answer 5

no and okay

Answer 6

There are other ways to do this problem. You could, for example, recognize that \[y=x^2+2x+1=(x+1)^2\]

Answer 7

nope not that either

Answer 8

Are you able to graph \[y=x^2?\]

Answer 9

yea

Answer 10

If you can, then all you have to do to obtain the graph of y=(x+2)^2 is to translate your entire graph 1 unit to the left. Try it:

Answer 11

okay is it b

Answer 12

Please explain your reasoning. Aren't you going to draw the graph of y=(x+1)^2?

Answer 13

i did draw it

Answer 14

I don't see your drawing. But then I didn't ask you to post it, as I should have.
But anyway. How did you decide that the correct answer is b?

Answer 15

my computer wont let me draw it on here so i did it on paper i found my notes a min ago
Finding the Vertex
Finding two points to left of axis of symmetry
Reflecting two points to get points right of axis of symmetry
Plotting the Points (with table)
Graphing the Parabola