Which expression is equivalent to (7^3)^-2? 1/7 x 7 x 7 x 7 x 7 x 7 7 1/6 x 6 x 6 x 6 x 6 x 6 x 6 1/7
@SolomonZelman @AnyTipzWouldHelp
\(\Huge\color{red}{ \rm (7^3)^{-2}=\frac{1 }{(7^3)^{2}} =\frac{1 }{7^{(3 \times 3)}} =? }\)
Dangit solomon, you type to fast. lol
Is it A?
I'll let him explain it, i'm on a couple other question right now, i can't sorry.
@SolomonZelman : That's incorrect - (7^3)^2 ≠ 7^(3x3).
it is none of your options, unfortunately.
Hint: (a^b)^c = a^(bc)
o: 2 Math Geeks fighting!! A NEVER BEFORE SEEN MOMENT!!!!!
Isn't it 7^(3x2)?
shiraz, you are confusing \[\Huge a^{b^c}≠a^{b+c}\]
I am relevantly bad at math, but this I do know .
My bad
it's 3 times 2...
the exponent I mean... ; sorry.
Okay, then it's A. Thanks
@SolomonZelman : Yes, your last post is correct. Indices work differently from normal mathematical operators. Some laws which you need to know are as follows: 1. a^b * a^c = a^(b+c) 2. (a^b)^c = a^(bc) 3. a^(b^c) = (a^b)^c
also @yellowlegoguy99 if your ever stuck in math, it's valuable to learn back roads to getting answers. If you have a calculator, just solve (7^3)^-2 on your calculator, then for each possible answer, work them out, so for A for instance, multiply 7 all those times, then divide by 1... you get the same answer, and therefore, you can induce that A is the right answer.
That's what I did lol
yes, shiraz I know the laws, I just really messed up on this one. dky .
It happens to everyone, no sweat.
@SolomonZelman : No worries - we all make mistakes at times - take care.
:)
My typo for Law #3 - I meant to type: a^b^c = a^(b^c) Sorry for the typo.
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