Question

Which operation would you use on the exponents to simplify the expression 5^7 × 5^11?

Addition

Subtraction

Multiplication

Division

Answer 1

@SolomonZelman @shiraz14

Answer 2

if we have 7, xs, multiplied together, and also have 11, xs, multiplied together; then what is the total number of xs that are multiplied together ?

Answer 3

So it's C?

Answer 4

.... how many xs do we have multiplied together? how do we determine the number of xs entotal that are multiplied together?

Answer 5

xs....?

Answer 6

So do you know PEMDAS and The Law of Exponents?

Answer 7

yeah, x^7 means: x*x*x*x*x*x*x ... 7 xs multiplied togehter

Answer 8

if we have 7 xs multiplied together, and 11 xs multiplied together, then how many xs entotal are mutliplied togther, and how do we figure that total out?

Answer 9

Duh I know pemdas and the law of exponents

Answer 10

(5 x 5 x 5 x 5 x 5 x 5 x 5) x (5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5)

Answer 11

78125 x 48828125

Answer 12

Ok now how many 5's are there in that?

Answer 13

7 5's and 11 5's

Answer 14

what operation can we use to determine the total number of 5s now?

Answer 15

I don't see how PEMDAS has anything to do with this, it's follows an exponent law.

\(\ \sf 5^7 = 5 \times 5 \times 5\times 5\times 5\times 5 \times 5\)

\(\ \sf 5^{11} = 5 \times 5\times 5\times 5\times 5\times 5\times 5\times 5\times 5\times 5\times 5\)

So, \(\ \sf 5 \times 5 \times 5\times 5\times 5\times 5 \times 5\) \(\ \sf 5 \times 5\times 5\times 5\times 5\times 5\times 5\times 5\times 5\times 5\times 5\) = 5^?

Or, simply apply the law of exponents, \(\ \sf \Large x^2 \times x^3 = x^{2+3} = x^5 \)

Answer 16

See this is what you do:

5^7 x 5^11 - (5x5x5x5x5x5x5) x (5x5x5x5x5x5x5x5x5x5x5)

Count how many fives are there ALL TOGETHER.

There is 18 5's

What did you do to know how many 5's where there?
Basically you are simplifying the exponents into one exponent.

Answer 17

5^18

Answer 18

I know @tHe_FiZiCx99 I just read the problem wrong at first.. Now @yellowlegoguy99 what did you do to get 5^18?

Answer 19

Yes, \(\ \sf 5^7 \times 5^{11} = 5^{7 + 11} = 5^{18} \)

Answer 20

@yellowlegoguy99 What did you do to get 5^18... You added/multiplied/divided/subtracted (choose which one) 7 and 11 to get 18