this chick needs help! any one of you guys? please:):)
The scale factor of two similar triangular prisms is 2. The volume of the smaller prism is 52 yd3. What is the volume of the larger prism?
I just want some one to explain! 3 people have tried. still don't get it:/
Isn't this the exact same problem we were working on just a few minutes ago? If so, please delete this new post.
mathmale!!!!!!!
yes, \(\LARGE\color{blue}{ \bf MATH }\)male !!!!!!!!
Yes? I spent 15 minutes or so with you on this same problem; including a strong hint on what to do next towards finding your own solution. Did you take my hint?
why do I have to delete it? I need help and the way people are explaining it doesn't make sense! thank you solomonzelman!:)
no11 I don't understand! and this has to be trned in in like 5 min.
If the volume of the smaller prism is \[V=\frac{ 1 }{ 2 }b*h*l,\] the volume of the larger prism can be found by replacing b with (2b), h with (2h) and l with (2l). Please do this algebra now.
id be like 6 1/2
I'd like to see your work, please. In this formula:\[V=\frac{ 1 }{ 2 }b*h*l,\] replace that "b" with "(2b)." What does the formula now look like?
Write it out, please.
ok im obviously stupid so ill just guess
hey thanks:/
If we replace b with 2b, h with 2h, and l with 2l, we get this formula for the volume of the larger prism:\[V _{larger prism}=\frac{ 1 }{ 2 }(2b)(2h)(2l)\]
Can you factor out the three 2's you see in the numerator?
\[V _{larger prism}=\frac{ 1 }{ 2 }(2b)(2h)(2l) = 2*2*2*\frac{ 1 }{ 2 }b*h*l\]
Please note that that \[\frac{ 1 }{ 2 }b*h*l=52yd ^{3}\]
So, given that, what is the volume of the larger prism?
Note: If the "scale factor" relating two similar solids is 2, that means you multiply every dimension within the formula for the volume of the first solid by 2. That's what we've done here.
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