Question

need help will give medal +fan :-) Trigonometry.

i have 5 questions

what is the amplitude period and phase shift of f(x)=-3 cos (4x+pi)+6?

a.) amplitude =3 , period = pi/2 , phase shift; x=-pi/4

b.) amplitude =-3, period =pi/2, phase shift : x=pi/4

c.)amplitude = -3 , period =-pi/2, phase shift : x=-pi /4

d.)amplitude =3 , period =2n, phase shift :x=-pi/4

Answer 1

@TERM_THE_INATOR @ganeshie8 @rock_mit182 @secret66

Answer 2

@beccaboo333 @thomaster @hartnn @HelpBlahBlahBlah

Answer 3

@whpalmer4 @robtobey

Answer 4

@RadEn @radar

Answer 5

@crabby_patty

Answer 6

i think it is b. am i right

Answer 7

\[f(x) = A \cos(B(x + C)) +D\]

Amplitude is \(A\)
Period is \(\dfrac{2\pi}{B}\)
Phase shift is \(C\)
DC offset is \(D\)

Answer 8

i know i just reread that in my book i justa wanted a second opinion do you think b is right? @whpalmer4

Answer 9

so, looking at your equation:

\[-3\cos(4x+\pi) + 6 = -3\cos (4(x+\frac{\pi}{4}) + 6\]\[-3\cos (4(x+\frac{\pi}{4}) + 6=A\cos(B(x+C))+D\]\[A = -3,B=4,C=\frac{\pi}{4},D=6\]

so amplitude is \(-3\), period is \(\dfrac{2\pi}{4 }= \dfrac{\pi}{2}\), phase shift is \(\dfrac{\pi}{4}\)

If that matches B, then B is correct.

Answer 10

yes thank you its always nice to have a second opinion