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Mathematics 17 Online
OpenStudy (anonymous):

how to convert 90% confidence level into a z score

OpenStudy (kropot72):

You need to use an Inverse Normal Probability Table. My table converts 90% confidence interval to \[z=\pm1.6449\]

OpenStudy (anonymous):

but i can use only standard normal table and i have to show how i find the answer step by step

OpenStudy (kropot72):

Just look for the cumulative probability value of 0.45 in your standard normal distribution table. It lies between 0.4495 and 0.4505. The z-scores for these are as follows: 0.4495: z=1.64 0.4505: z=1.65 Now you need to take the average of these two z-scores. The value will not be exactly the same as given by the Inverse Normal Probability Table. Remember to give the positive and negative values.

OpenStudy (anonymous):

ok but how did u get 0.45

OpenStudy (kropot72):

The total area under the standardized normal distribution curve corresponds to a cumulative probability of 1. The 90% confidence interval corresponds to an area of 0.9 centered on a mean of 0. 0.9/2 = 0.45.

OpenStudy (anonymous):

thanks

OpenStudy (kropot72):

You're welcome :)

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