Question

What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)?

Answer 1

the distance between (-2,0) and (2,-3) will give us the radius

Answer 2

\[\sqrt{(-3-0)^{2}+(2-(-2)^{2}}\]

Answer 3

radius is 5

Answer 4

i tried doing the problem but i got it wrong . i put the radies as 25 @strenesmee

Answer 5

(x-2)^2+(y-(-3))^2=25
x^2-4x+4+y^2+6y+9=25
x^2-4x+y^2+6y-12=0

Answer 6

what about this ? im not very good at geomtry & im trying but its kind of confusing , what about this

A circle is described by the equation (x−12)2+(y−32)2=49. What are the cordinates for the center of the circle and the length of the radius?

Answer 7

@strenesmee

Answer 8

the equation for a circle is like this
(x-a)^2+(y-b)^2=r^2
here a stands for x axis of the center and b stands for y axis of the center and r is the radius of the circle
can you guess the answer??

Answer 9

(-1/2,-3/2), 2/3units

(-1/2,-3/2), 4/9units

(1/2,3/2), 4/9units

(1/2,3/2), 2/3units
these are the answer choices . i cant really take a wild guess

Answer 10

first try to get an equation like that
(x-a)^2+(y-b)^2=r^2