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Chemistry 12 Online
OpenStudy (anonymous):

How many grams of ammonium sulfate are needed to make a 0.25 M solution at a concentration of 6 M? I don't even know where to start this problem. Explanation PLEASE!! Award for best answer!! THANKS!!

OpenStudy (anonymous):

@whpalmer4 @thomaster @Luigi0210

OpenStudy (anonymous):

I really get chemistry but this question makes no sense to me!!!

OpenStudy (anonymous):

Well. I think we need more information.

OpenStudy (anonymous):

That is literally exactly what the question says and that is why I am so confused!!

OpenStudy (anonymous):

Molarity is moles/liters of solvent. Without knowing either the amount of solute or the amount of solvent, we can't really do much. ._. If we had one of the other values we could do figure it out.

OpenStudy (anonymous):

I know exactly what you are saying I found the answer online and it is 171.2 grams but I am not interested in the answer I am interested in understanding that's why I am so frustrated!! Hopefully you knowing the answer will help somewhat :)

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

That makes no sense. 1 mole of (NH4)SO4 is 132.1 grams. 171.2/132.1 is about 1.3 moles. Grrr.

OpenStudy (whpalmer4):

Yeah, the problem was corrupted in transit. Look here and you'll see a version of it which makes much more sense! http://chemistryatsouthcarletonhs.wikispaces.com/file/view/Molarity+Practice+Problem1.doc

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