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Mathematics 7 Online
OpenStudy (muzzack):

HELLLLLLPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

no

OpenStudy (muzzack):

Fiber-optic cables are used widely by broadcast and cable companies. When light passes through a fiber-optic cable, its intensity decreases with the increase in the length of the cable. If 1000 lumens of light enters the cable, the intensity of light decreases by 1.2% per meter of the cable. Part A: Can this situation be represented by an exponential function? Justify your answer. (2 points) Part B: Write a function f(x) to represent the intensity of light, in lumens, when it has passed through x meters of the cable. (4 points) Part C: Some scientists are trying to make a cable for which the intensity of light would decrease by 8 lumens per unit length of the cable. Can this situation be represented by an exponential function? Justify your answer and write the appropriate function to represent this situation if 1000 lumens of light enter the cable. (4 points)

OpenStudy (anonymous):

lol

OpenStudy (muzzack):

man this is hell

OpenStudy (muzzack):

@Hero @whpalmer4 @wwhitlock @wifibasedgod @Whitemonsterbunny17 @escapeshipshape @eifhbiew

OpenStudy (muzzack):

okay um well its asking that can it be a exponential function

OpenStudy (muzzack):

idk

OpenStudy (muzzack):

thx @Hero

OpenStudy (muzzack):

well it could be like this \[f(x)=1000(1.03)^{x}\]

OpenStudy (muzzack):

sorry \[f(x) = 1000(0.2)^{}\]

OpenStudy (muzzack):

\[^{x}\]

OpenStudy (muzzack):

\[f(x) = 1000(0.2)^{x}\]

OpenStudy (muzzack):

ok @Hero i think i can because there is a principal and a average rate of change so yes right?

OpenStudy (muzzack):

@Hero are you thar

OpenStudy (muzzack):

@FlvsGirl @thomaster

OpenStudy (muzzack):

@whpalmer4 @ganeshie8

hero (hero):

The situation appears to be linear: \(f(x) = 1000 - 1000(0.012)x\)

OpenStudy (muzzack):

omg thx

OpenStudy (muzzack):

there is another questions that i would need help

OpenStudy (muzzack):

could you please help me

OpenStudy (muzzack):

if i could give an amount of medals, it would be 20

hero (hero):

All you have to do is just post your questions. If someone wants to help, they will help. In the mean time, while waiting, you can attempt the problem on your own. Taking initiative with attempting to solve your own problem helps. Asking good questions helps as well.

OpenStudy (muzzack):

oh ok, i mean i already did i just want to see and double check :)

OpenStudy (muzzack):

medal for @Hero literally a hero

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