Question

@ganeshie8 attached inside:)

Answer 1

The mass of the cube is increasing at a rate of _________ grams per hour.

Answer 2

differentiate the Mass with.respect.to \(t\)

Answer 3

how would i set that up? :/

Answer 4

\(M = x^3 + 0.1x^4\)


\(\dfrac{dM}{dt} = ?\)

Answer 5

3x^2 + (3)0.1x^3 ?

Answer 6

3x^2 + 0.3x^3 ?

Answer 7

Nope. you're differentiating with respect to time, \(\color{red}{t}\)

Answer 8

so u need to use chain rule, okay ?

Answer 9

ahh :/ not sure how to do this then :(

so t=0.05? :/

Answer 10

\(M = x^3 + 0.1x^4\)


\(\dfrac{dM}{dt} = 3x^2 \dfrac{dx}{dt} + 0.1*4x^3 \dfrac{dx}{dt}\)

Answer 11

And you're given the length, \(x\) is increasing at a rate of \(0.05\) cm/hr
that means \(\dfrac{dx}{dt} = 0.05\)

Answer 12

plug that in dM/dt equation

Answer 13

ganeshie8 can you answer my question next...everyone keeps not helping me right

Answer 14

okay, so 3x^2(0.05) +0.1 * 4x^3(0.05) ?

what would i plug in for x? 0.05 also?

Answer 15

@ganeshie8 ? :/

Answer 16

sorry i got aw snap'd :/

Answer 17

@ShelbyRenaebb , sure :)

Answer 18

use wolfram @iheartfood
http://www.wolframalpha.com/input/?i=3*3%5E2*0.05+%2B+0.1*4*3%5E3*0.05

Answer 19

no worries! i just have to leave in one minute! :/

Answer 20

so the answer is 1.89 ?

Answer 21

Correct !

Answer 22

perfect timing!! ahha thank you1! :)

Answer 23

u wlc :)