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1. Look at the cone above. If R=6 cm and H=8 cm, what is the surface area of the cone? Surface Area of a Cone = r(l + r) where l is the slant height
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Well this is a right cylinder cone. Therefor the area is equal to \[\pi*r(r+\sqrt{h^2+r^2}))\]
\[6\pi(6+\sqrt{64+36})\]
\[6\pi(6+\sqrt{100})\]\[6\pi(6+10)\]\[16*6*\pi = 96\pi\]
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