PLEASE HELP WILL GIVE MEDAL!! :) Find the vertices and foci of the hyperbola with equation ((x+1)^2)/16 - (y+5)^2/9 =1

Question

anonymous · Answer

$$a^2=16$$ a=4
$$b^2= 9$$  b=3

the center is (1,5) (I got the 1 from the x+1 and the 5 from y+5) 
the vertices are 4 units from the center on either side of the x axis so that means it would be (5,5) and (-3,5) 
the foci are found with the equation $$c^2=a^2+b^2$$ 
so C^2= 16 + 9 or C^2= 25 or c=5 so that means the foci are 5 units from the center (6,5) and (-5,5)

anonymous · Answer

did that help?

anonymous · Answer

http://www.purplemath.com/modules/hyperbola2.htm this might help