A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved? Show your work. (µC = 1.0 × 10–6 C)

Question

ganeshie8 · Answer

sorry i dont remember these.. :( @sourwing

loser66 · Answer

you have the formula on it
$\triangle U= \dfrac{1}{2}CV^2$ so that you can calculate the V from it, just plug in the numbers. Don't forget convert the unit

nali · Answer

you could use this formula: Energy= q (charge) x Voltage (or potential difference)

nali · Answer

now since the distance is not given, then $$\Delta V = V$$

so just plug in the formula 10J= (5 x 10^-6) V

so V = 10J/ (5 x 10^-6)

idkwut · Answer

2*10^6 = 2000000 or 2.0 x 10^6 ? @Nali

nali · Answer

wait what is your question?

idkwut · Answer

I'm giving you the solution lol. I'm asking for confirmation.

nali · Answer

I actually got 5 x 10^ 6 V

idkwut · Answer

@Loser66 We both have different solutions! Can you confirm?

loser66 · Answer

2000V

loser66 · Answer

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