Question

The differential equation dy/dx = y/x^2 is has a solution given by:

Answer 1

a. y = Csqrt(x^2+4)
b. y = Ce^(-1/x)
c. y=-1/2e^(x^2) + C
d. x^2 + y^2 = C
e. y=Ce^(-kt)

Answer 2

The answer is b.

Answer 3

I will tell you why

Answer 4

ok

Answer 5

\[
\frac{dy}{dx}= \frac {y}{x^2}\\
\frac{dy}{y}= \frac {dx}{x^2}\\
\ln(y)=-\frac {1}x+K\\
y=e^{-\frac {1}x+K}=e^K e^{-\frac {1}x }=C e^{-\frac {1}x }
\]

Answer 6

Thank you, you have been very helpful. :D I can understand your work clearly. Hopefully I past the AP exam next month. Well, it's midnight so I think I will be heading out. Thanks again!

Answer 7

YW
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