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Mathematics 15 Online
OpenStudy (anonymous):

The length of one leg of a right triangle is 24 ft, and the length of the hypotenuse is 40 ft. What is the length of the other leg? A. 64.0 feet B. 32.0 feet C. 6.3 feet D. 46.7 feet

OpenStudy (anonymous):

pythagorean theorem

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

ok. sounds like you got it then

OpenStudy (anonymous):

but i still dont get how to do it

OpenStudy (anonymous):

|dw:1398317018882:dw| 2^2+c^2=8^2 solve for c. this is the basic concept

OpenStudy (anonymous):

A. 64.0 ?

OpenStudy (rulnick):

For right triangle problems, always look first to see if the three sides make a Pythagorean triple; especially look for 3:4:5. If the three sides are in the ratio 3 to 4 to 5, the problem is easy. Three 8's are 24, and five 8's are 40. So the missing side must be four 8's :)

OpenStudy (anonymous):

so for my question wouldnt it be a

OpenStudy (rulnick):

No, it wouldn't be (A). You want 24:(something):40 to be in the ratio 3:4:5. Multiply 3, 4, and 5 each by 8 to see what the missing "something" must be.

OpenStudy (anonymous):

super metroid!

OpenStudy (rulnick):

(And the Pythagorean Theorem still applies: 24 squared + ? squared = 40 squared.)

OpenStudy (rulnick):

Points for you, recognizing a metroid :)

OpenStudy (anonymous):

always!

OpenStudy (anonymous):

B.

OpenStudy (anonymous):

seems legit.

OpenStudy (anonymous):

i knew that it was a metroid but wanted to keep it on subject

OpenStudy (anonymous):

1600-500something. sqrt of 1100 something is 30 something.

OpenStudy (rulnick):

Yes, B is legit. 24:32:40 is 3:4:5. Or, yes, the missing side is sqrt( 40^2 - 24^2 ).

OpenStudy (anonymous):

What are the solutions to the equation x2 = 64? A. 8 only B. 32 only C. 8 and –8 D. 32 and –32

OpenStudy (anonymous):

thanx

OpenStudy (rulnick):

Welcome.

OpenStudy (anonymous):

b?

OpenStudy (anonymous):

there will be 2 answers. as long as that says x^2

OpenStudy (anonymous):

d

OpenStudy (anonymous):

do you know what the inverse operation of exponents are?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

so what is the inverse operation of x^2

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