Question

How do you solve this?

Answer 1

first find the points of intersection by equating two equations
x^2+y^2-6x+8=x^2+y^2-6
6x=14 x=2.33

Answer 2

find the equation of the circle that passes through (2.33, 0) and (1,1)

Answer 3

equation
(x-a)^2+(y-b)^2=r^2
a,b =1, 1 and the distance between the points will give you the radius r

Answer 4

I did it this way : tell me if i'm correct

family of circles say S+xS'=0

=> x^2 + y^2 - 6 + x(x^2 + y^2 - 6x + 8) =0
from there, I get x as 1,
Which gives the equation as : 2x^2 + 2y^2 - 6x + 2 = 0

=> x^2 + y^2 - 3x +1 =0 ,,


IS THIS CORRECT??

Answer 5

@hartnn

Answer 6

@Compassionate

Answer 7

@kc_kennylau

Answer 8

@strenesmee

Answer 9

@ganeshie8

Answer 10

Looks good !

Answer 11

thanks!