Hi you guys! I need some help finding the discriminate of "y=x^2-13x+42.25".. Would anyone like to help? :)
1. Scary pic. 2. Did you mean the "discriminant"?
discriminant is b^2-4ac a 1 b -13 c 42.25
Is that all that is to it? Yes, I do mean discriminant lol sorry!! And thank you thank you, my pic is very scary I suppose :p
So when solving, do I leave out "a" and solve with just b and c by plugging them into the above equation?
Yes, that is all to it. @rulnick has very nicely given you the values of a, b and c. Using these values, you find what the expression \(b^2 - 4ac\) evaluates to.
In a quadratic \(ax^2 + b x+ c = 0\), \(b^2 - 4ac\) is the discriminant.
I got -169-169, I don't feel as if this is correct :c Am I right?
Well, almost so. But \(b^2 = (-13)^2 = 169\) as the square of a negative is also positive.
ah, because a negative and negative multiplied together creates a positive. So the CORRECT answer would be 169-169? Thank you for helping btw :D
Yes... what is 169 minus 169?
zero
So the discriminant is zero?
yes
So, would you mind steering me in the next direction? I need to know which would be the best method of finding the x-intercepts algebraically.. I'm not quite sure how to go about knowing this
The x-intercept is when the value of the quadratic becomes zero.
My homework would like to know though, would factoring, quadratic formula, completing the square, etc. be the best method of solving
So based off of what I have, How am I sure?
For this case, you can use any of the above.
Oh alright, well that's awesome for my assignment! :) Would any of them be a better choice to go with?
Really, I'd prefer none over the other. But one thing that's worth a mention: did you know that a quadratic with discriminant zero is a perfect square?
No, I didn't happen to know this, but I did just get done working with perfect squares awhile ago in my AlgII course and I'm familiar with them. And thank you, I'll just pick one and solve; I appreciate your time! c:
No problem! I may prove it to you using the quadratic formula, if you want...
I would love to watch! Just more demonstration for me, which is helpful always
\[x = \dfrac{-b\pm \sqrt{b^2 - 4ac}}{2a}\]Note how that thing within the square root is the discriminant? That's the reason why it's so important to calculate. Anyway, if the discriminant is zero, then\[x = \dfrac{-b \pm \sqrt{0}}{2a}=\dfrac{-b}{2a}\]So basically, we get only one unique root. But you know that a quadratic with only one unique root is a perfect square...
Oh my, it makes perfect sense now that I see how it is related and comes together
Haha!
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