Can someone please help me???

Question

anonymous · Answer

With?...

anonymous · Answer

about ?

anonymous · Answer

$$\sqrt{2x+15}-x=6$$

anonymous · Answer

would I add the x to the other side and take the square of both sides and then unfoil it and solve?

anonymous · Answer

Ok, let me lead you through the steps:

sqrt(2x + 15 - x) = 6
sqrt(x + 15) = 6
sqrt(x) = -9

This is how that looks:
$$\sqrt{x} = -9$$

anonymous · Answer

i thought you are suppose to move the x down first?

anonymous · Answer

What do you mean by "moving the x down first?"

anonymous · Answer

because the x is not in the square root?

anonymous · Answer

I mean its not a part of whats inside the square root sign

anonymous · Answer

Oh, well i didn't know because it wasn't in parenthesis >.<

anonymous · Answer

opp sorry

anonymous · Answer

Let me rework it.

anonymous · Answer

sqrt(2x+15)-x=6
(sqrt(2x+15)^2=(6+x)^2
2x+15=36+2x+x^2
-21=x^2
x=sqrt(-21)

anonymous · Answer

x=i *sqrt(21)

anonymous · Answer

$$x = \sqrt{-21}$$ is correct.

anonymous · Answer

ok so you would basically move the x, take the square root, unfoil it and solve it down for x?

anonymous · Answer

Yup :)

anonymous · Answer

you wouldnt need to solve it in quadratic form due to the x^2

anonymous · Answer

in my solution 
something wrong in third line the equation is 
2x+15=36+12x+x^2
x^2+10x+21=0
(x+7)(x+3)=0
x=-3,-7

anonymous · Answer

oh okay that makes more sense thank you soooo much