Question

Factor.

m2 + 12m + 36

(Points : 1)
(m + 6)^2

(m – 6)^2

(m + 36)^2

Cannot be factored

Answer 1

D , cannot be factored

Answer 2

Not true!

Answer 3

@dsfasdfasdfga please come back and I'll teach you how to factor this.

Answer 4

@Briaa420 that invitation applies to you as well

Answer 5

Alrighty im listening

Answer 6

To factor something of the form \[ax^2+bx+c\]multiply the values of \(a\) and \(c\) together. For this problem, \(a =1, b = 12, c = 36\), so \(a*c = 36\)

Now, find two factors of \(a*c\) that add up to \(b\).

36= 1*36
36 = 2*18
36 = 3*12
36 = 4*9
36= 6*6

6+6 = 12, so we will use 6 and 6.

Rewrite the polynomial, splitting the middle term into two terms using those factors we found:

\[m^2 + 6m + 6m + 36\]Now group each pair of terms:
\[(m^2+6m) + (6m + 36)\]Factor each group separately:\[m(m+6) + 6(m+6)\]Look at that — each group has a common factor of \((m+6)\), so factor it out:
\[(m+6)(m+6) = (m+6)^2\]

Check by multiplying out the factoring to make sure we get our original back:
\[(m+6)(m+6) = m(m+6) + 6(m+6) = m*m+6m + 6m + 36\]\[\qquad=m^2+12m+36\checkmark\]

Answer 7

i never knew that ! so which one would be the answer choice?

Answer 8

@whpalmer4

Answer 9

Oh its (m+6) ^2

Answer 10

A

Answer 11

Yes, A would be the correct answer choice:

\[(m+6)^2 = (m+6)(m+6) = m(m+6) + 6(m+6) = m^2 + 6m + 6m + 36\]\[\qquad = m^2+12m+36\]