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when the following chemical reaction is balanced, what number is placed before NH3? N2+3H2&NH3 A)1 B)2 C)3 D)6
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\( \rm N_2 + 3 H_2 \longrightarrow NH_3 \) Your goal is to set coefficients so that there are the same number of atoms of each element on both sides of the reaction. So, start with Nitrogen. \( \rm \color{lime}{N}_\color{green}{2} + 3 H_2 \longrightarrow \color{lime}N\color{green}{H_3} \) On the left-side, we have two nitrogen atoms. On the right, we only have one. We need to set a coefficient on the NH3 so that it has two nitrogen atoms. Is that clear?
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