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Solve the following inequality: 13 – 2x ≥ 7
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you have to get x by itself
you would would have to subtract anything on the side of x
pretend your solving an equation that says 13-2x=7
is it 3?
Don't be intimidated by the inequality symbol; the rules of algebra still apply. One can subtract 13 from both sides to get -2x ≥ -6. Multiplying by a -1, flips the sign, and yields 2x ≤ 6. Dividing by a 2 yields x ≤ 3. The mysterious part of that is the flipping of the sign. However, that can be avoided by first adding the 2x to both sides: 13 ≥ 7 + 2x Now we subtract the 7: 6 ≥ 2x And divide by the 2: 3 ≥ x.
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yes it is 3 now you just add the sign back and it should be \[x \le3\]
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