Question

A CYLINDER OF COMPRESSED GAS HAS A VOLUME OF 60L AND A PRESSURE OF 10 ATM. WHAT VOLUME WOULD GAS OCCUPY IF ALLOWED TO ESCAPE INTO A BALLOON AT A PRESSURE OF 1.5 ATM?

Answer 1

i KNW I HAVE TO CONVERT BUT IDK WAT TO CONVERT FIRST

Answer 2

@Ashleyisakitty

Answer 3

@AnImEfReaK

Answer 4

@AccessDenied

Answer 5

ITS BOYLES AND DALTONS LAW

Answer 6

V1P1=V2P2- use this formula. You change atm to kpA. 1 atm = 101.3 kpa. You leave volume in litres as it is.

Answer 7

OH I FORGOT TO MENTION ASSUME THERE IS NO TEMPERATURE CHANGE

Answer 8

WOULD THE V1 BE THE ORIGINAL VOLUME?

Answer 9

Ok no problem. If 1 atm = 101.3 Kpa
then... 10 atm * 101.3 kpa / 1atm. That's your first conversion of 10 atm into kpa. (21)
then... 1.5 atm * 101.3 kpa/1atm . That's your second convertion of 10 atm into kpa. (P2)

Answer 10

V1 is the volume they gave you. You are figuring out V2.

Answer 11

OK HOLD ON LET ME WRITE THIS DOWN

Answer 12

Alright :)

Answer 13

P1** NOT 21 typing error ***

Answer 14

OKAY SO FOR P1 I GOT 1,013 KPA

Answer 15

AND P2 I GOT 151.95 KPA

Answer 16

V1 IS 60 L

Answer 17

HOW DO U FIND V2?

Answer 18

Now find V2 by substituting those known values into the equation.

Answer 19

V1*P1=V2*P2 just re-arrange to solve for V2.

Answer 20

SO I MULTIPLY THE FIRST TWO NUMBERS AND DIVIDE BY THE SECOND #

Answer 21

Can you type that up for me in equation format?

Answer 22

Like how I did above ^

Answer 23

SO 60*1,013=60,780/151.95=400 L =V2

Answer 24

Yes, that is correct :)

Answer 25

OH OK HEY CAN U HELP WITH ONE MORE ITS CAUSE THEY ASK ME TO USE A CHART AND IDK HOW TO USE IT AND THANKS:)

Answer 26

Alright ^^

Answer 27

THIS IS THE CHART

Answer 28

So what's the question?

Answer 29

THIS IS THE QUESTION

Answer 30

#9

Answer 31

Alright did you get the first right?

Answer 32

YEA

Answer 33

Then what are you having difficulty with exactly? If you could do that question the rest will be easy.

Answer 34

I FORGOT HOW I SOLVED IT

Answer 35

Oh, ok. Are you familiar with PV = nRT?

Answer 36

NO

Answer 37

I HAVENT DONE CHEM IN A WHILE

Answer 38

Ok P is our pressure, V volume, n moles, R gas constant 8.314 and T temperature is specific.

Answer 39

Step 1: In the question they gave you T. But its in degrees Celcius. It must be converted to K, Kelvin.
0 degrees Celcius = 273.15 degrees Kelvin
so.. 28 degrees Celsius = how many K?

Answer 40

103.15 KELVIN

Answer 41

How did you get that?

Answer 42

OH WAIT DONT U SUBTRACT 273 AND 103.15

Answer 43

Where is the 103.15 coming from?

Answer 44

IDK I DID MY MATH WRONG BUT I REMEBER MY TEACHER SAID SOMETHING ABOUT SUBTRACTING

Answer 45

Don't get Kpa confused with Kelvin, use the rule above- do you get it?

Answer 46

There is addition here 28 + 273.15...

Answer 47

OH YEA

Answer 48

Remember 273.15 represents 0 degrees celcius.

Answer 49

301.15?

Answer 50

And we are adding 28 to it.

Answer 51

Yes.

Answer 52

SO P IN THE FORMULA IS 301.15?

Answer 53

Step 2: Covert 0.985 atm to Kpa like i taught you in the previous question.

Answer 54

No that's T temperature.

Answer 55

That's why you may have got confused...

Answer 56

OH OK

Answer 57

Step 2: That will give you P for pressure.

Answer 58

Do you get it so far?

Answer 59

400.95 IS P?

Answer 60

Its 0.985 atm * ? what's your calculation?

Answer 61

to convert to kPa.

Answer 62

*101.32500KPA

Answer 63

1 ATM =101.32500

Answer 64

So try multiplying again.

Answer 65

AND I GOT 0.985*101.32500 AND THE CALCULATOR GAVE ME 400.95?

Answer 66

NVR MIND I GOT 99.80

Answer 67

Now that's right.

Answer 68

I got 99.8 on both computer and hand held calculators just to make sure :)

Answer 69

OK HOW DO U FIND R AND N?

Answer 70

R is a fixed gas constant. 8.314.

Answer 71

n is what you are solving for because they gave V.

Answer 72

So step 3: Convert 624cm^3 into L, if 1L = 1000cm^3

Answer 73

You devide the 624 by ? to get 1L?

Answer 74

divide*

Answer 75

I DIVIDE 1000CM^3 AND 624?

Answer 76

No you only divide 624 by 1000 here.

Answer 77

IM CONFUSED SO WAT TO NUMBERS DO I DIVIDE?

Answer 78

FOR THE PROBLEM

Answer 79

Okay,
If 1L = 1000 CM^3
(We want Volume in Litres here)
We are given 624cm^3 to make that into litres, divide it by 1000.
See, 624 cm^3 * 1L/ 1000 cm^3.

Answer 80

Get it so far?

Answer 81

YES COUNTINUE

Answer 82

So what is your V in Litres now?

Answer 83

242,970.624 BUT IT MIGHT BE TRICKY CAUSE ITS AN IPHONE CALCULATOR

Answer 84

624/ 1000 = 0.624.

Answer 85

OH ITS CAUSE I INCLUDED THE ^3

Answer 86

That's just the unit- apart of cm^3.

Answer 87

OH OK

Answer 88

You only use the numbers in your calculations.

Answer 89

Step 4: You have R- its a fixed gas constant- its value is 8.314.

Answer 90

Now can you list for me the values of V, R, P and T we collected? You need them to find n.

Answer 91

SO WAIT MY V IS 0.624

Answer 92

AND I KNW P IS 99.80 T IS 301.15 R IS 8.314

Answer 93

Okay, substitute then all in the ideal gas law to find n PV = nRT.

Answer 94

WATS THE UNIT FOR THE R? AND PV=NRT SO (99.80)(0.624L)=N(8.314 )(301.15 KPA)

Answer 95

OH AND FOR THE FIRST PART I GOT 62.27?

Answer 96

J/K/mol is the unit of the gas constant.

Answer 97

WOULD THE FIRST PART BE 62.27 L OR KPA?