Question

Let http://i.imgur.com/v7iEMfG.png model the horizontal distance in meters traveled by a projectile. If the initial velocity is 36 meters/second, which equation would you use to find the angle needed to travel 100 meters?
7.36sin(2) = 100
132.12sin(2) = 100
264.49sin(2) = 100
100sin(2) = 100

Answer 1

hi ;)

Answer 2

hi

Answer 3

xD

Answer 4

;D

so:
\[\large h = \frac {v_o}{4.9} \sin \theta \cos \theta\] ... yeah ?

Answer 5

sorry, it just looked cut off at the end, wanted to make sure that's the full eqn first?

Answer 6

@ShantelT1 ...?

Answer 7

yes it is sorry

Answer 8

\[\large h = \frac {v_o}{4.9} \sin \theta \cos \theta\]
so if u want h to = 100 m
and u have v initial @ 36 m/s
\[\large 100 = \frac {36}{4.9} \sin \theta \cos \theta\]
\[\large 100 = 7.3469 \times \sin \theta \cos \theta\]
\[\large \frac {100}{7.3469} =\sin \theta \cos \theta\]
\[\large 13.611 = \sin \theta \cos \theta\]
and
\[\large \sin \theta \cos \theta\ = \frac 12 \sin (2 ~\theta )\]
so
\[\large 13.611 = \frac 12 \sin (2 ~\theta )\]
\[\large 27.222 = \sin (2 ~\theta )\]

... can u solve from here @ShantelT1 ?

Answer 9

so it is the first one?

Answer 10

there's no angle in any of ur options...?

Answer 11

unless it means:
\[\large 7.36 \times \sin(2\theta ) = 100\]?
in which case i think it's still wrong...
\[\large \frac 12 \times 7.36 \times \sin(2\theta ) = 100\] is more correct, yeah?

Answer 12

@robtobey or @jim_thompson5910 could you help us out here if u have a sec, i'm confused ???

Answer 13

@iPwnBunnies or @hartnn ... du u have a sec to check something ?

Answer 14

:S i hate trig

Answer 15

im kinda certain this lines right... sinθcosθ =1/2sin(2 θ), s'just that it now doesnt match n e of ur answers ... >:(
darn answers...

Answer 16

:/

Answer 17

k im out, answer A looks the closest to right... sooooooo yeah.... sorry :'(

Answer 18

i think theta is 14.185 if that helps at all...?