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solve using Cramer's Rule only : 3x+4y-3z=5 3x-2y+4z=7 3x+2y-z=3
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The system can be written in the form of a matrix like this: \[\left[\begin{matrix}3 & 4 & 5 \\ 3 & -2 & 4 \\ 3 & 2 & -1\end{matrix}\right] \left[\begin{matrix}5 \\ 7 \\3\end{matrix}\right]\] Confirm if this is understandable
yes can you please show me how to solve it step by step plz
hello, yes So cramer's rule is being used to efficiently solve for x, y or z which one do you want to solve ?
x y and z
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please and thank you
ok lets begin by solving X so to use cramer's rule here, we simply replace all entries belonging to x variable with the solution vector. The first entry in each row is the one that is connected to x |dw:1398451703435:dw|
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