Question

Find the equation of the axis of symmetry.
y- -4x^2-16x-3

Answer 1

Do you know the quadratic formula?\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 2

Know what? If you take just the \[\frac{ -b }{ 2a }\] part, that's the x-coordinate of your vertex. And the "axis of symmetry" is the vertical line whose equation is x=-b?2a.

Hope this info ties this all together for you!

Answer 3

Okay, so if my coordinates are (-2,13) How would I write that in my axis of symmetry?

Answer 4

Actually, Candy, you graph the vertical line x=-2 first. Then, if y ou wish, mark y=13 on that line; that will be your VERTEX.

The eq'n of the A. of Symmetry is simply x=-2.