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OpenStudy (mallorysipp234):
If cos Θ = 4/7, what are the values of sin Θ and tan Θ?
12 years ago
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OpenStudy (mallorysipp234):
@mathmale @satellite73
12 years ago
OpenStudy (mallorysipp234):
@saifoo.khan
12 years ago
OpenStudy (mallorysipp234):
@ranga
12 years ago
OpenStudy (mallorysipp234):
@ShaTay
12 years ago
OpenStudy (anonymous):
I have No clue... sorry
12 years ago
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OpenStudy (ranga):
Use the identity sin^2(x) + cos^2(x) = 1.
Plug in the value of cos(x) into the above identity and solve for sin(x).
Them, tan(x) = sin(x) / cos(x).
12 years ago
OpenStudy (anonymous):
can't you use a calculator? in scientific mode
12 years ago
OpenStudy (mallorysipp234):
I still dont understand.
12 years ago
OpenStudy (ranga):
sin^2(x) + cos^2(x) = 1
cos(x) = 4/7
sin^2(x) + (4/7)^2 = 1
sin^2(x) + 16/49 = 1
sin^2(x) = 1 - 16/49 = (49-16)/49 = 33/49
sin(x) = sqrt(33/49) = sqrt(33) / 7.
tan(x) = sin(x) / cos(x) = sqrt(33) / 7 * 7 / 4 = sqrt(33) / 44
12 years ago
OpenStudy (mallorysipp234):
@ranga
12 years ago
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OpenStudy (ranga):
You can also solve this problem by drawing a triangle, marking one of the non-ninety degree angle as x, using the definition of cos(x) to identify the adjacent and hypotenuse, etc.: |dw:1398453721088:dw|
12 years ago
OpenStudy (ranga):
In my reply before last, tan(x) = sqrt(33)/4 (not 44).
12 years ago
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