If cos Θ = 4/7, what are the values of sin Θ and tan Θ?
@mathmale @satellite73
@saifoo.khan
@ranga
@ShaTay
I have No clue... sorry
Use the identity sin^2(x) + cos^2(x) = 1. Plug in the value of cos(x) into the above identity and solve for sin(x). Them, tan(x) = sin(x) / cos(x).
can't you use a calculator? in scientific mode
I still dont understand.
sin^2(x) + cos^2(x) = 1 cos(x) = 4/7 sin^2(x) + (4/7)^2 = 1 sin^2(x) + 16/49 = 1 sin^2(x) = 1 - 16/49 = (49-16)/49 = 33/49 sin(x) = sqrt(33/49) = sqrt(33) / 7. tan(x) = sin(x) / cos(x) = sqrt(33) / 7 * 7 / 4 = sqrt(33) / 44
@ranga
You can also solve this problem by drawing a triangle, marking one of the non-ninety degree angle as x, using the definition of cos(x) to identify the adjacent and hypotenuse, etc.: |dw:1398453721088:dw|
In my reply before last, tan(x) = sqrt(33)/4 (not 44).
Join our real-time social learning platform and learn together with your friends!