Need help with two area questions ! (Pictures Below)
use trigonometry
No trigonometry needed for the first one
have you covered the 30-60-90 and 45-45-90 rules yet?
Yes, but I dont know how to do them
Careful on the first one...cause the numbers don't match the scale of the drawing at all!
the 1st one pretty much is just the 45-45-90 rule the 2nd one uses the 30-60-90 rule -> http://grockit.com/blog/wp-content/uploads/2011/04/111.jpg <--- notice the ratios for both rules
Actually on the first one, you just need to recognize that the triangle is isosceles
|dw:1398457797937:dw|
so once you know one side for the triangle, you can get the "opposite" or vertical line length recall that a triangle's area is "base times height" so the base is 8
so the shape is a rectangle and a triangle, get their independent area and sum them up to get the area of the shape
Okay so i did the 45-45-90 thing, and i got 11.31 for the hypotenuse
do i even have to get the hypotenuse to solve that problem?
one the 2nd picture is the 30-60-90 rule you're already given one side, 8 notice is a rhombus, thus 4 equal triangles so you get the "vertical line" or height for that triangle, get its area and do that 4 times since there are 4 triangles to get the area of the shape
Okay
Driana_18 you do not need the hypotenuse, or slanted side for the triangle's area you need the "vertical line" |dw:1398458172508:dw|
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