yherthyerhyr
does the ! mean factorial?
yes
Do u have choices?
nope
I think its 8n-5 but that might be wrong..and what do u mean by its factorial..that may help me a little more
(4n+4)!=(4n+4)(4n+3)(4n+2)(4n+1)(4n)(4n-1)(4n-2)(4n-3)(4n-4)!
Oh its 16n^2+4n..does that sound like the right answer..U should give me a medal sinne I helped u too;)
thanks dude..anymore questions??
no thats not it. i put it in as the answer and it said it was wrong.
okay well then try 8n-5 and if that not right tell me and i will try to solve it
yeah thats not it either
okay umm..how about (4n)x(4n+1) I havent done this before so i am trying the best i can
cancel!
no worries. thanks for the help. ill figure it out
@satellite73 cancel!?
hahah sorry
\[\frac{(4n+4)(4n+3)(4n+2)(4n+1)(4n)(4n-1)!}{(4n-1)!}\] s a start
oooohhh ok. so its just (4n+4)(4n+3)(4n+2)(4n+1)(4n)?
when you cancel, you are left with the remaining 5 terms in the numerator yes
this is confusing when you first see it, but as you can see factorials often cancel like mad
\[\frac{(n+1)!}{n!}=n+1\] for example
thanks so much @satellite73
yeah this is way over my head..is this calculus or something??
its covered in both algebra 2 and pre-calc. im in pre-calc
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