Question

@Nurali @ranga @helpme1.2 @AccessDenied @thadyoung

Answer 1

You know that the standard form of a circle is:
\( (x - h)^2 + (y - k)^2 = r^2 \) ?
If so, what were your thoughts on a possible approach here?

Answer 2

The one thing we should be especially careful of here is that the graph is labelled in twos. So we will have to estimate that the half-way point is the odd integer between the two. E.g. going along the horizontal, it seems the center of the circle aligns between 2 and 4. We could estimate this to be the odd number between the two, 3.

Answer 3

The center of the equation I wrote is at (h, k). Where is the center for the circle on the graph?

Answer 4

3

Answer 5

3 is the x-value. And the y-value?
Center point: (3, _)

Answer 6

2

Answer 7

Not quite; it is below the x-axis, so that has to be negative, right?
so your center is at (3, -2). That part is clear?

Answer 8

sorry, yes -2

Answer 9

Yup. Then the only other part we need for the equation is the radius. So we can use a point on the circle and the center to determine that, although you can see it is easy to count as well.

Answer 10

i think B

Answer 11

Yup, that looks good!
We place in the values of k=-2 and h=3 along with radius r=3.
(x - 3)^2 + (y - -2)^2 = 3^2
(x-3)^2 + (y+2)^2 = 9 looks good! :)

Answer 12

yayyyy!!! thank you!! :D

Answer 13

Glad to help! :)