Please help me evaluate! tan(sin^-1(-5/9))
Trigonometric Functions
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what would i do to find tan(x)??
is there a formula?
To find AB use pythagoras
but how can i find anything without A and B having any numbers to enter into a formula?
Let sin^-1(-5/9) = x sin(x) = -5/9 tan(x) = opposite / adjacent = AC / AB = 5 / AB. AB can be found from AB^2 + AC^2 = AC^2
Or tan(x) = sin(x)/cos(x) But u still have to find adjacent for it
I meant Pythagoras theorem u can't use PYTHOGARAS because he is already dead I know it was a lame joke
lol okay so i now know that i need to do ab^2 + ac^2 = ac^2 but how do i get the numbers? :(
AC = 5, BC = 9 (see the diagram).
In a Right-angled triangle , Sum of the squares of two sides = the square of the hyptenuse
It should be AB^2 + AC^2 = BC^2
SOH CAH TOA
I got 10.3
You wrote the formula incorrectly
am i wrong :O
i meant ali
I will have to check
okay because if i am right I'm still not sure what to do after lol
Are u screwed with your basics
AB^2 = 9^2 - 5^2. AB = ?
well I'm doing an online class with no textbook or teacher so what i do know i either taught myself or learned from youtube and math isn't my best subject, so i guess so
no problem but don't jump the gun then u won't understand future concepts if you are not knowing the fundamentals
ranga, i got 2sqrt14
Find AB. Find tan(x). Stick a negative sign in front of it because inverse sine of -5/9 is a negative angle and is in the fourth quadrant where tan is negative.
oh wow, i see what happened there!
Yes, AB = 2sqrt(14). tan(x) = AC/AB = - 5 / (2sqrt(14))
Alright.
would the answer be -5sqrt14/28? because i have to multiply by sqrt 14
Yes. Most teachers and textbooks don't like a radical in the denominator and so you will have to rationalize the denominator by multiplying top and bottom by sqrt(14). You will get -5sqrt(14) / 28.
awesome, thank you so much!! :)
You are welcome.
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