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the expression cos (pi - x) is equivalent to
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- cos(x)
thank you! can you explain how to got that?
Use the identity cos(x-y) = cos(x)cos(y) + sin(x)sin(y) to get... cos(pi - x) = cos(pi)*cos(-x) + sin(pi)*sin(-x) cos(pi - x) = cos(pi)*cos(x) - sin(pi)*sin(x) cos(pi - x) = -1*cos(x) - 0*sin(x) cos(pi - x) = -cos(x)
yes well u know it's a formula that cos(a-b)=cosa cosb+sina sinb
You also can think that on the unit circle the angle x and \(\pi-x\) are symmetric with respect to the y-axis, then \( \cos(\pi-x) =-\cos(x)\)
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