How to I find the two values of theta in degrees (0 deg <_ theta <_ 360 deg) for tan theta = sqrt 3 using the unit circle?
p.s. i know how to find sine and cosine, just need help finding tangent! :)
What can you tell me about special angles?, can you draw the unit circle?
Ah, ok so how do you express tangent in terms of sine and cosine?
i have a picture of it right in front of me, i just don't know what i should be looking for
would tangent represent x?
\[\tan(\theta)=\sqrt3\] means \[\frac{\sin(\theta)}{\cos(\theta)}=\sqrt3 \]which will occur if \[\sin(\theta)=\frac{\sqrt3}{2}, \cos(\theta)=\frac{1}{2}\] because \[\frac{\frac{\sqrt3}{2}}{\frac{1}{2}}=\sqrt3\]
no, so here is an important identity. Tan x= (sin x) / (cos x)
would that be 5pi/6 pi/6 and pi/3?
think about the value of sine cosine and tangent, in which quadrant are they all positive?
in quadrant 1
so the two values would just be pi/3 and pi/6 @FibonacciChick666 ??
You should only have one answer, check their sines and cosines only one yields the correct answer
but the problem says to find two values
well, one of those
there is another quadrant where the tangent would be positive
hence your other answer
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