Question

how do i find the two asymptotes and period for y=tan(x/3)?

Answer 1

y=tan(x/3)=sin(x/3)/cos(x/3)
Asymptotes occur when cosx/3=0.
x=(2n+1)*(pi/2)
put n=0,1,2
and generally period of tan(kx)=pi/k

Answer 2

why am i putting n=0,1 & 2 if i only need 2 asymptotes?

Answer 3

it should be 0,1

Answer 4

so for 0 i got pi/2

Answer 5

and for 1 i got 3pi/2. would those be the two asymptotes?

Answer 6

or would one of the asymptotes be 3?

Answer 7

it should be
x/3=(2n+1)*(pi/2)

Answer 8

okay so then 3pi/2 and 9pi/2 is what i got. is that correct?

Answer 9

and the period would be pi/3?

Answer 10

here k=1/3

Answer 11

is k=1/3 the period of part of the formula to find the asymptotes?

Answer 12

i think asymptotes are all right and for period p=pi/k=pi/(1/3)=3(pi)

Answer 13

oh okay, thank you for your helP! :)