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Mathematics 18 Online
OpenStudy (anonymous):

Just want to make sure I am correct

OpenStudy (anonymous):

if \[x+3\div3=y+2/2 \]

OpenStudy (anonymous):

then \[x/3 = ?\]

OpenStudy (anonymous):

y/2 ? right ?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

It is y/2.

OpenStudy (anonymous):

@matricked why did you say no

OpenStudy (anonymous):

isnt y/3

OpenStudy (anonymous):

It is (x+3)/3,and not x+3/3.

OpenStudy (anonymous):

that is an option

OpenStudy (anonymous):

see x+3/3 = y+2/2 x+1=y+1 hence x=y and thus x/3 and y/2 aren't same...

OpenStudy (anonymous):

A. y+1 B. y/3 C. y/2 D. y-1

OpenStudy (anonymous):

b

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

@matricked It is (x+3)/3,and not x+3/3

OpenStudy (anonymous):

no

OpenStudy (anonymous):

what would be the difference?

OpenStudy (anonymous):

(x+3)/3 = x/3 +3/3 =x/3 +1 but x+3/3 =x+1

OpenStudy (anonymous):

The correct option is (c). x+3/3=x+1 and (x+3)/3=x/3+1.

OpenStudy (anonymous):

oh wait |dw:1398493207674:dw|

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