Solve for x and y.
i wasn't done posting my question
@hartnn @wolf1728
where are x and y ?
x is hypotenuse and y is opposite
@hartnn
To find the hypotenuse, use the Pythagorean theorem. You have width and height already. Am I missing something in your drawings?
Umm i think you're on the wrong track @hartnn what does she mean i'm confused ?
you have pasted a wrong diagram....i guess i seee rectangles :P
ohh i apologixe hold on a sec
no that's the wrong picture @meshlogic
y=16sqrt*sin(30) =8sqrt(3)
Yes, trig functions.
so x is hypotenuse y is opposite and 16sqrt3 is adjacent
y=16sqrt*cos(30) =16*sqrt(3) *sqrt(3)/2 =24
Sin = opposite/hyp; x is adjacent, so sin(30) = y/13sqrt3; making y = 16sqrt3*sin(30)
I was thinking sin too
I got your msg ,Shay...I just can't respond because you didn't fan me back.
ohh lol sorry
Lol, it's ok
x = 16sqrt3*cos(30)
because cosine = adj/hyp
you just confused me all the way ok so wait should we be using cos and tan ?
noo;; use sin and cosine; you use sin to find opposite side when you know the angle and the hypotenuse; you use cos to find the adjacent side when you know the angle and the hypotenuse
Do you know SOHCAHTOA? It is an acronym for "sin = opp/hyp, cos = adj/hyp, tan = opp/adj" think if it like you americans have Pocahontas :)
sin 30 = .5
that's right
so 16sqrt(3)*0.5 = y
.054
thats y right ?
I get 13.85...(irrational number). So I think you entered it in your calculator wrong. Do: sin(30)*16*sqrt(3)
Or \(sin(30)*16*(3)^{1/2}\)
now i got .931
I'm sorry but @hartnn can you take over from here please i need to hurry up
i can't take over with all that explanation....i u want i can start over, but that'll take time
I'll post a new question for this
Sorry you are confused with my advice. :) Good luck and someone else will take over.
Thank you @meshlogic i just dnt understand what you're trying to say it's not you it's me
You're doing well and the fact that you are trying says a lot about you and future success :)
Aww thanks :)
Gee, I'm joining this post kind of late. Anyway, the triangle shown is a 30° 60° 90° triangle whose sides are always in the ratio of 1, sqrt(3), 2. So, if the "medium" side is 16*sqrt(3) then the short side is 16. (The long side would be 32).
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