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Mathematics 48 Online
OpenStudy (anonymous):

Solve for x and y.

OpenStudy (anonymous):

i wasn't done posting my question

OpenStudy (anonymous):

@hartnn @wolf1728

hartnn (hartnn):

where are x and y ?

OpenStudy (anonymous):

x is hypotenuse and y is opposite

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

To find the hypotenuse, use the Pythagorean theorem. You have width and height already. Am I missing something in your drawings?

OpenStudy (anonymous):

Umm i think you're on the wrong track @hartnn what does she mean i'm confused ?

hartnn (hartnn):

you have pasted a wrong diagram....i guess i seee rectangles :P

OpenStudy (anonymous):

ohh i apologixe hold on a sec

OpenStudy (anonymous):

no that's the wrong picture @meshlogic

OpenStudy (anonymous):

OpenStudy (anonymous):

y=16sqrt*sin(30) =8sqrt(3)

OpenStudy (anonymous):

Yes, trig functions.

OpenStudy (anonymous):

so x is hypotenuse y is opposite and 16sqrt3 is adjacent

OpenStudy (anonymous):

y=16sqrt*cos(30) =16*sqrt(3) *sqrt(3)/2 =24

OpenStudy (anonymous):

Sin = opposite/hyp; x is adjacent, so sin(30) = y/13sqrt3; making y = 16sqrt3*sin(30)

OpenStudy (anonymous):

I was thinking sin too

OpenStudy (anonymous):

I got your msg ,Shay...I just can't respond because you didn't fan me back.

OpenStudy (anonymous):

ohh lol sorry

OpenStudy (anonymous):

Lol, it's ok

OpenStudy (anonymous):

x = 16sqrt3*cos(30)

OpenStudy (anonymous):

because cosine = adj/hyp

OpenStudy (anonymous):

you just confused me all the way ok so wait should we be using cos and tan ?

OpenStudy (anonymous):

noo;; use sin and cosine; you use sin to find opposite side when you know the angle and the hypotenuse; you use cos to find the adjacent side when you know the angle and the hypotenuse

OpenStudy (anonymous):

Do you know SOHCAHTOA? It is an acronym for "sin = opp/hyp, cos = adj/hyp, tan = opp/adj" think if it like you americans have Pocahontas :)

OpenStudy (anonymous):

sin 30 = .5

OpenStudy (anonymous):

that's right

OpenStudy (anonymous):

so 16sqrt(3)*0.5 = y

OpenStudy (anonymous):

.054

OpenStudy (anonymous):

thats y right ?

OpenStudy (anonymous):

I get 13.85...(irrational number). So I think you entered it in your calculator wrong. Do: sin(30)*16*sqrt(3)

OpenStudy (anonymous):

Or \(sin(30)*16*(3)^{1/2}\)

OpenStudy (anonymous):

now i got .931

OpenStudy (anonymous):

I'm sorry but @hartnn can you take over from here please i need to hurry up

OpenStudy (anonymous):

hartnn (hartnn):

i can't take over with all that explanation....i u want i can start over, but that'll take time

OpenStudy (anonymous):

I'll post a new question for this

OpenStudy (anonymous):

Sorry you are confused with my advice. :) Good luck and someone else will take over.

OpenStudy (anonymous):

Thank you @meshlogic i just dnt understand what you're trying to say it's not you it's me

OpenStudy (anonymous):

You're doing well and the fact that you are trying says a lot about you and future success :)

OpenStudy (anonymous):

Aww thanks :)

OpenStudy (wolf1728):

Gee, I'm joining this post kind of late. Anyway, the triangle shown is a 30° 60° 90° triangle whose sides are always in the ratio of 1, sqrt(3), 2. So, if the "medium" side is 16*sqrt(3) then the short side is 16. (The long side would be 32).

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