Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the rule (x+7, y−1) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.
Please help anyone pleaaassseeeee
Well take all the x values and add 7 then take all the y values and subtract them by 1
So here's an example using point A (-2,2) -2+7=5 2-1=1 So A'=(5,1)
ok let me try
So what do you get for B'?
so for b -2+7=5 4-1=3
c is 2+7=9 4-1= 3
Yupp perfect!
d 2+7 =9 and 2-1= 1
am i on the right track here
ok so i got the new coordinates
now this part Describe what characteristics you would find if the corresponding vertices were connected with line segments.
Maybe it'd help if you graphed it for yourself. Visual might make it easier
definitly :)
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