Question

Help please!

If f(x)= integral of 1-5x to 5 (sin(t))/1+t^2 dt, then f'(x)=???

Answer 1

http://en.wikipedia.org/wiki/Leibniz_integral_rule use this rule

Answer 2

f'(x)=[sin5/(1+5^2)]*[d/dx(5)]-[sin(1-5x)/(1+(1-5x)^2)]*d/dx(1-5x)

do u get it?

Answer 3

so this term [sin5/(1+5^2)]*[d/dx(5)] will be 0

Answer 4

result will be =[5*sin(1-5x)]/(27-10x)

Answer 5

I still don't get it :(

Answer 6

And the answer you put up I tried to type into the answer box and it shows it is wrong

Answer 7

we never learned about leibniz's integral rule :(

Answer 8

use this and see what u get