Proportion: (2+√2)/(2-√2) = x/(3+√10)
\[(3 + \sqrt{10}) \dot\ \frac{2 + \sqrt{2}}{2 - \sqrt{2}}= x\]
Shouldn't we cross-multiply? With (3+√10) * (2+√2)?
That's the part that's confusing me.
Yes, you should
So, how did you get what you put above?
I Multiplied both sides by \(3 + \sqrt{10}\)
I'll try to show what I'm confused about...
This is what I thought it would be: \[x = ((3+\sqrt{10})(2 + \sqrt{2}))/(2 - \sqrt{2})\] So I don't get how we multiply both of (2+√2) / (2-√2) by (3+√10).
What you have is correct. You only multiply it with the numerator.
Oh okay...so how do we proceed/
Think of it this way \[\frac{a}{b} \times \frac{c}{d} = \frac{ab}{cd}\] So \[\frac{3 + \sqrt{10}}{1} \dot\ \frac{2 + \sqrt{2}}{2 - \sqrt{2}}= \frac{(3 + \sqrt{10})(2 + \sqrt{2})}{2 - \sqrt{2}}\]
Yes, I get that.
To multiply \((3 + \sqrt{10})(2 + \sqrt{2})\) use the distributive property
So, would that be: (6 + 3√2 + 2√10 + √20)?
Looks right
Alright, can you help me in dividing that by (2-√2)?
\[(6 + 3√2 + 2√10 + √20)\div (2-√2)\]
Hang on
Multiply the left side of the proportion by the conjugate first \[\frac{(2+√2)}{(2-√2)} \times \frac{2 + \sqrt{2}}{2 + \sqrt{2}} = \frac{x}{(3+√10)}\]
Then simplify
Would that be 3 = x/(3x + √10)?
You have to multiply it all out properly.
Use FOIL to multiply if you have to
I'm getting 1 now, if I did it correctly.
No, you did not do it correctly. Post your steps here so I can point out what you are doing wrong.
(2 + √2)(2 + √2) 4 + 2√2 + 2√2 + √4 4 + 4√2 + 2 6 + 4√2 (2 - √2)(2 + √2) 4 + 2√2 - 2√2 - √4 4 - 2 = 2 (6 + 4√2)/2
That's better, but you're not done simplifying
Would it be 3 + 2√2?
Yes, now multiply both sides by \(3 + \sqrt{10}\) to isolate \(x\)
(3 + √10)(3 + 2√2) 9 + 6√2 + 3√10 + 2√20
Yes, but now you have to simplify \(2\sqrt{20}\)
9 + 6√2 + 3√10 + 2√20 2√ 4 * 5 4√5 9 + 6√2 + 3√10 + 4√5
Congrats
Thank you so much!
yw
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