A workman's hammer slips from his grasp as he works on an office building 265 feet above street level. The hammer is subject to the acceleration (downward) due to gravity, $32 ft/sec^2$. Find the terminal speed of the hammer at the impact with the ground(in $ ft/sec$, 2 DP) and the duration of the fall (in seconds, 2 DP).

Question

anonymous · Answer

Ask google. They have all the answers

anonymous · Answer

$$a(t)=-32$$
$$v(t)=-32t+c$$ but since it is dropped and not thrown, $c=0$ making $v(t)=-32t$ and 
$$s(t)=-16t^2+265$$

anonymous · Answer

the time when it hits the ground is found by solving 
$$-16t^2+265=0$$  then the velocity will be found by taking $v$ at the resulting $t$