Solve for y: y+10/y+3 = y+1/y-1
13/7 13/5 41/5
14/5 I ment for the last one
\[y+\frac{ 10 }{ y }+3 = \frac{ y+1 }{y-1 }\]
If you'd like for me to guide you through the solution of this problem, or to help you check your own answer, fine. Which would it be?
plz walk me thrugh it
(Good response!!!!) Could you identify the LCD (lowest common denominator)?
I have no clue been forever since ive done this
All right. your equation has four terms (3 on the left, four on the right). Two of these terms are fractions. These fractions have different denominators. Multiply these two denominators together to get the LCD for this particular problem. The LCD is: ?
so I multiply 3 and -1 right? im sorry I know I sound stupid
Please do not tear yourself down, especially not here, where you have the chance to re-learn anything you've forgotten. Two of the four terms are fractions. One has the denominator y; the other has the denominator y-1. Therefore, multiplying these two dens. together, we get y(y-1). No need to multiply that out (yet). OK so far?
By the way, for clarification: The first fraction is 10/y. Its numerator is 10 and its denominator is y. Just a review. Your second fraction is (y+1) / (y-1). Its numerator is y+1 and its denominator is y-1.
Taking these two denominators and multiplying them together, we get y(y-1).
Allie, are you OK?
If not, what could I clear up for you?
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