how do I find the equation of the tangent line? Ex.) f(x)=-x^2+4x-5 at (2,-1)
do you mean the derivative?
Im not sure. It just says equation of the tangent line to the function at the given point
is that a homework you got from school? or did you find it by yourself?
from school
from a calculus or precalculus class I suppose right?
mihrib, don't give the answer, we are here to learn , not to have our homework solved
the equation of a tangent line of a function at (x0,y0) is:\[y=f'(x _{0})(x-x_{0})+y_{{0}}\]
I think (s)he doesn't know how to do the derivative
that's why I was asking you not to post
oh srry
i thought she knew derivatives
calculus.
yes I thought so, have they taught you how to make a derivative?
yes but I don't understamd at all
do you know derivatives?
see she knows derivatives
but she doesn;t understand them which is worse
okay, so let me try to explain what a derivative is
okay
i have to go anyway bi
what you were asked for was the tangent line to a curve that may look a little like this one |dw:1398560480884:dw|
(sorry I'm not good drawing) The derivative is precisely the tangent line to a curve at some specific point, in this case (2,-1)
it's like getting the slope of the curve
|dw:1398560616984:dw|
Join our real-time social learning platform and learn together with your friends!