When a circle is inscribed into a square, what is the ratio of the area of the circle to the area of the square?
you have to calulate the area of the circle and the square
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and using algebra you need to get that rate
so you first say that the area of the square has to be \[a^2\] as its area is side*side, and we take each side as a
and the area of the circle has to be \[\pi r^2=\pi (\frac{ a }{ 2 })^2\]
I see....thank you!
what you have to do to get the rate is divide the area of the circle by the area of the square
you get \[AreaRate=\frac{ \pi (\frac{ a }{ 2 })^2 }{ a^2 }\]
and plug in any number for "a", and solving that would give you the rate
\[\frac{ \pi (\frac{ a }{ 2 })^2 }{ a^2 }=\frac{ \pi \frac{ a^2 }{ 4 } }{ a^2 }=\frac{ \pi a^2 }{ 4a^2 }\]
So the rate would be pi to 4 right?
you eliminate the a^2 as it's multiplying and dividing and you get \[\frac{ \pi }{ 4 }\]
yep, which would be around 0.785
Thank you!
you're welcome!!
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